>>>Heat of Reaction Aim: To determine the heat of reaction of NaOH with HCl ApparatusMaterials: Polythene Cup, Thermometer, Measuring Cylinder, NaOH, HCl. Procedure: (1) 25cm" of HCl was placed in polythene cup, (2) HCl was left to stand for 5 minutes and then the temperature was taken (3) Steps 1-2 was repeat with NaOH instead of HCl, (4) NaOH was added to HCl in polythene cup and stirred for 5minutes and the highest temperature the liquid rose …showed first 75 words of 247 total…

…showed last 75 words of 247 total…X (38˚- 32˚) NaOH = 630J (NaOH) = 025kg X 4200 X (38˚- 31˚) HCl = 735J (HCl) = 630J (NaOH) + 735J (HCl) = 1365J Conclusion: An exothermic reaction takes place when NaOH is mixed with HCl. The amount of heat produced when .0025 moles of NaOH is mixed which .0025 Moles of HCl is equal to 1365J and the amount of heat that will be produced when 1mole of NaOH reacts with 1mole of HCL will be equal to ((1 moles .1mole) X 1356j), 546KJ